The areas of two similar triangles are 25 cm² and 36 cm² respectively. If the altitude of the first triangle is 3.5 cm then the corresponding altitude of the other triangle is

Given: Area of triangle 1 = 25 cm²

Area of triangle 2 = 36 cm²

Altitude of triangle 1 = 3.5 cm

To find: Altitude of triangle 2

Let the altitude of triangle 2 be x.

∵ The areas of two similar triangles are in the ratio of the squares of the corresponding altitudes.

∴ We have,

⇒ x = √17.64 = 42 cm