In an equilateral triangle with side a, prove that area = .
Let ∆ ABC be an equilateral triangle with side a.
To prove: Area of ∆ ABC =
In ∆ ABC, AD bisects BC
Now, in ∆ ACD
Using Pythagoras theorem,
AC2 = AD2 + DC2
⇒ AD2 = AC2 – DC2
Now, in ∆ ABC
Area of ∆ ABC =