Integrate the functions.


Let 6x + 7 =

6x + 7 = A(2x - 9) + B


Now, equating the coefficients of x and constant term on both sides, we get,


2A = 6


A = 3


-9A + B = 7


B = 34


6x + 7 = 3 (2x - 9) + 34




Now,


Let x2 – 9x + 20 = t


(2x - 9)dx = dt


----------(1)


And


x2 – 9x + 20 =




…(2)


Thus, from (1) and (2), we get,




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