Integrate the functions.
⇒
Now, Let us consider
Let x2 + 2x + 3 = t
⇒ (2x + 2)dx = dt
… (1)
And, now let us consider
⇒ x2 + 2x + 3 = x2 + 2x + 1 + 2 = (x +1)2 + (2
Using eq. (1) and (2), we get,