Integrate the rational functions.
Let
⇒ x = A(x + 2) + B(x +1)
On comparing the coefficients of x and constant term, we get,
A + B = 1
2A + B = 0
On solving above two equations, we get,
A = -1 and B = 2
Thus,
= -log|X + 1| + 2log|x + 2| + C
= log (x+2)2 – log |x + 1| + C