Integrate the rational functions.
Let 
⇒2x – 3 = A(x - 1)(2x + 3) + B(x + 1)(2x + 3) + C(x+1)( x – 1)
⇒ 2x – 3 = A(2x2 + x – 3) + B(2x2 + 5x + 3) + C(x2 - 1)
⇒2x - 3 = (2A + 2B + C)x2 + (A + 5B)x + (-3A + 3B – C)
Equating the coefficients of x2 and x, we get,
B =
, A = 
and C = 
Thus,
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