Find the integrals of the functions.

tan³2xsec2x = tan²2xtan2xsec2x

= (sec²2x -1)tan2xsec2x

= sec²2x.tan2xsec2x-tan2xsec2x

⇒

⇒

Now, Let sec2x = t

⇒ 2sec2xtan2x dx = dt

Thus,

⇒

⇒