Find the area of the circle 4x² + 4y² = 9 which is interior to the parabola x² = 4y.

It is given that of circle, 4x² + 4y² = 9 and parabola x² = 4y.

On solving the above two equations, we get the point of intersection

We can see that the required area is symmetrical about y axis.

Thus, Area OBCDO = 2 × Area OBCO

Let us draw BM perpendicular to OA.

⇒ The coordinates of M are (, 0).

Then, Area OBCO = Area OMBCO – Area OMCO

Therefore, the required area OBCDO is

units