Find the area bounded by curves (x – 1)2 + y2 = 1 and x2 + y2 = 1.



It is given that area of circle, (x – 1)2 + y2 = 1 and x2 + y2 = 1.


On solving the above two equations, we get the point of intersection



We can see that the required area is symmetrical about x axis.


Thus, Area OBCAO = 2 × Area OCAO


Let us draw AM perpendicular to OC.


The coordinates of M are (, 0).


Then, Area OCAO = Area OMAO + Area MCAM









Therefore, the required area OBCAO


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