In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

2x + 3y – z = 5


The eq. of the plane

2x + 3y-z = 5


Direction ratio of the normal (2, 3, -1)





This is the form of


lx + my + nz = d ( d = Distance of the normal from the origin.)




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