In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

5y + 8 = 0

The eq. of the plane

0x-5y + 0z = 8

Direction ratio of the normal (0, -5, 0)

= 5

This is the form of

lx + my + nz = d (∴ d = Distance of the normal from the origin.)

Direction cosine = 0, -1, 0