Find the equations of the planes that passes through three points.

(1, 1, –1), (6, 4, –5), (–4, –2, 3)


The given points are (1, 1, -1), (6, 4, -5), (-4, -2, 3).

Let,



= 1(12 - 10) – 1(18 - 20) -1 (-12 + 16)


= 2 + 2 – 4


= 0


Since, the value of determinant is 0.


Therefore, these points are collinear as there will be infinite planes passing through the given 3 points.


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