In each of the question verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:

y = ex + 1 : y′′ – y′ = 0


It is given that y = ex + 1

Now, differentiating both sides w.r.t. x, we get,



Now, Again, differentiating both sides w.r.t. x, we get,



y” = ex


Now, Substituting the values of y’ and y” in the given differential equations, we get,


y” – y’ = ex - ex = RHS.


Therefore, the given function is the solution of the corresponding differential equation.


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