In each of the question verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:
y = x2 + 2x + C : y′ – 2x – 2 = 0
It is given that y = x2 + 2x + C
Now, differentiating both sides w.r.t. x, we get,
⇒ y’ = 2x + 2
Now, Substituting the values of y’ in the given differential equations, we get,
y’ – 2x -2 = 2x + 2 – 2x - 2 = 0 = RHS.
Therefore, the given function is the solution of the corresponding differential equation.