For each of the differential equations given in question, find the general solution:

It is given that ![]()
This is equation in the form of
(where, p = secx and Q = tanx)
Now, I.F. = ![]()
Thus, the solution of the given differential equation is given by the relation:
y(I.F.) = ![]()
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⇒ y(secx + tanx) = secx + tanx – x+ C
Therefore, the required general solution of the given differential equation is
y(secx + tanx) = secx + tanx – x+ C.