For each of the differential equations given in question, find the general solution:


It is given that


This is equation in the form of (where, p = and Q =)


Now, I.F. =


Thus, the solution of the given differential equation is given by the relation:


y(I.F.) =


-----------(1)


Now, Let t = tanx




sec2xdx = dt


Thus, the equation (1) becomes,






tetanx = (t – 1)et + C


tetanx = (tanx – 1)etanx + C


y = (tanx -1) + C e-tanx


Therefore, the required general solution of the given differential equation is


y = (tanx -1) + C e-tanx.


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