Find the probability of throwing at most 2 sixes in 6 throws of a single die.

Question

Philoid · Accepted Answer

In this question, let us assume X represent the number of times of getting sixes in 6 throws of a die

Also, the repeated tossing of die selection are the Bernoulli trials

Thus, probability of getting six in a single throw of die,

Clearly, we have X has the binomial distribution where n = 6 and

And,

∴

_{Hence, probability of throwing at most 2 sixes = P (X ≤2)}

_{= P (X = 0) + p (X = 1) + P (X = 2)}