Find the probability of throwing at most 2 sixes in 6 throws of a single die.


In this question, let us assume X represent the number of times of getting sixes in 6 throws of a die

Also, the repeated tossing of die selection are the Bernoulli trials


Thus, probability of getting six in a single throw of die,


Clearly, we have X has the binomial distribution where n = 6 and


And,






Hence, probability of throwing at most 2 sixes = P (X ≤2)


= P (X = 0) + p (X = 1) + P (X = 2)









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