In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is


In this question, let us assume X represent the number of times selecting defected bulbs in a random sample of given 5 bulbs


Also, the repeated selection of defective bulbs from a box are the Bernoulli trials


Clearly, we have X has the binomial distribution where n = 5 and


And,






Hence, probability that none bulb is defective = P (X = 0)





option C is correct

14
1