If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?


We know that, in a leap year there are total 366 days, 52 weeks and 2 days

Now, in 52 weeks there are total 52 Tuesdays


Probability that the leap year will contain 53 Tuesdays is equal to the probability of remaining 2 days will be Tuesdays


Thus, the remaining two days can be:


(Monday and Tuesday), (Tuesday and Wednesday), (Wednesday and Thursday), (Thursday and Friday), (Friday and Saturday), (Saturday and Sunday) and (Sunday and Monday)


Total Number of cases = 7


Cases in which Tuesday can come = 2


Hence, probability (leap year having 53 Tuesdays)


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