Boron has two stable isotopes, 10 5 B and 11 5 B. Their respective masses are 10.01294 u and 11.00931 u, and the atomic mass of boron is 10.811 u. Find the abundances of 10 5 B and 11 5 B.

Question

Philoid · Accepted Answer

The atomic mass of the two isotopes of Boron (¹⁰₅B and ¹¹₅B) are given as 10.01294 u and 11.00931 u

Let their abundances be respectively, x and (100-x) percent.

Hence from the formula discussed in previous question,

10.811 =

So, x = 19.89% and (100-x) = 80.11%

Hence the abundance of ¹⁰B₅ is 19.89% and that of ¹¹B₅ is 80.11%

Boron has two stable isotopes, 105B and 115B. Their respective masses are 10.01294 u and 11.00931 u, and the atomic mass of boron is 10.811 u. Find the abundances of 105B and 115B.

Boron has two stable isotopes, ¹⁰₅B and ¹¹₅B. Their respective masses are 10.01294 u and 11.00931 u, and the atomic mass of boron is 10.811 u. Find the abundances of ¹⁰₅B and ¹¹₅B.