Obtain the binding energy (in MeV) of a nitrogen nucleus (¹⁴₇N) given m (¹⁴₇N) = 14.00307 u

The number of neutron and Proton both are 7 in a ¹⁴N₇ atom.

The mass defect Δm = m_p + m_n-m_N

And Binding energy is given by E_B = Δmc²

Mass of a proton = 1.007825 u

Mass of a neutron = 1.008665 u

In this case mass defect = Δm = 7 × (1.007825 + 1.008665)-14.00307u = 0.11236 u

We know, 1 u = 931.5 MeV/c²

So, E = Δmc² = 0.11236 × 931.5 (MeV/c² × c² ) = 104.66334 MeV

Hence, Binding energy of ¹⁴N₇ = 104.66334 MeV