Evaluate


Let I =

Let x2 + 1 = t …(i)


d(x2 + 1) = dt


2x dx = dt


x dx = dt/2


When x = 2; t = 22 + 1 = 5


When x = 3; t = 32 + 1 = 10


Substituting x2 + 1 and x dx in I


I = []


I =


I = � log 2


= � log 2


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