If a point A(0, 2) is equidistant from the points B(3, p) and C(p, 5), then find the value of p.
The figure will be drawn as
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Since, point A is equidistant from points B and C. We can write in the form,
BA = AC …(i)
Now, length BA = ![]()
And length AC = ![]()
Substituting lengths BA and AC in equation (i), we get
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Squaring both sides, we get
(3 – 0)2 + (p – 2)2 = (0 – p)2 + (2 – 5)2
⇒ 9 + p2 + 4 – 4p = p2 + 9
⇒ 4p = 4
⇒ p = 1
Hence, the value of p is 1.