Find the value of k so that the quadratic equation kx (3x - 10) + 25 = 0, has two equal roots.

kx(3x-10) + 25=0
3kx²-10kx + 25=0

This is a quadratic equation of form ax² + bx + c=0

Where a=3k, b=-10k ,c=25

For equal roots, D=0

D=b²-4ac=0

Substituting the values of a,b and c

(-10k)²-4(3k)(25)=0

⇒ 100k²-300k=0

⇒ 100(k²-3k)=0

⇒ k(k-4)=0

There are two possible values of k, k=0 and k=3

But if k=0, then the equation will not remain quadratic,
∴ k=3.