The radius of a circle is 13 cm and length of one of its chords is 24 cm. Find the distance of the chord from the centre.

Let AB = 24 cm be the chord of the circle with radius AO = 13 cm.
Draw OP ⊥ AB. Join OA according to theorem,
AP= 휤 = 12 cm
In Δ APO, ∠P = 90°
.^.. AO² = AP² + OP²
        = 12² + OP²
⇒ 13² = 12² + OP²
⇒ OP = 5 cm