Determine the length of a chord, which is at a distance of 5 cm from the centre of the circle of radius 13 cm.
Let AB be the chord of a circle of radius 13 cm.
Draw OD ⊥ AB, then OD = 5 cm
In ΔODB, ∠D = 90°
\\ OB2 = OD2 + DB2
⇒ 132 = 52 + DB2 ⇒ DB = 12 cm
Hence, AB = 2 × DB = 24 cm.
Draw OD ⊥ AB, then OD = 5 cm
In ΔODB, ∠D = 90°
\\ OB2 = OD2 + DB2
⇒ 132 = 52 + DB2 ⇒ DB = 12 cm
Hence, AB = 2 × DB = 24 cm.
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