Length of the bridge, AC = 150 m
Angle of elevation, θ = 45°
To find: Width of the bridge, AB
Solution:
In right angled Δ ABC,
sin θ = [Opposite] / [Hypotenuse]
sin 45° = AC/AB
And also the opposite side is AB and the hypotenuse side is AC
sin 45° = AB/AC
AB = AC sin 45 º
= 150 × (1 / √2)
= 150 × 1.414
= 106.066 m
Therefore the width of the river is 106.07 m.