A flag-staff stands at the top of a 5 m high tower. From a point on the ground,the angle of elevation of the top of the flag-staff is 60º and from the samepoint, the angle of elevation of the top of the tower is 45º. Find the heightof the flag-staff.


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Given:

Height of the tower, h = 5 m

Angle of elevation of the top of the flag staff, θ = 60°

Angle of elevation of top of tower, ϕ = 45 °

To find: Height of the flag staff.

Solution:


Let BC be the height of the tower and DC be the height of the flag-staff.


In right angled Δ ABC,


AB = BC cot 45°


AB = 5 m ………………….(i)


In right angled Δ ABD,


AB = BD cot 60°


AB = (BC + CD) cot 60°


AB = (5 + CD)
× ( 1 / √ 3) ………………….(ii)


Equating (i) and (ii)


(5 + CD)
× (1 / √ 3) = 5


(5 + CD) = 5
× (√ 3)


CD = (5×
√ 3 ) - 5

= 5(1.732 - 1)

= 5 × 0.732

= 3.66 m


Therefore the height of the flag-staff is 3.66 m

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