A man standing 'a' metres behind and opposite the middle of a football goalobserves that the angle of elevation of the nearer cross-bar is α and that ofthe further crossbar is β. Show that the length of the field is, a(tanα cotβ +1).


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Given:


Let AB and CD be the cross bars of the football goal.


Let O be a point, 'a' metres behind and opposite the middle of the football goal.


Let 'l' metres be the length of the field.


Let AB = CD = p m since AB and CD are the cross bars of the football goal.


In right angled ΔBAO,

AB / AO = tan α

AO = p / tan α


In right angled ΔDCO,

CD / CO = tan β

CO = p / tan β


Length of the field = AO + OC


= a + (l - a)


=
( p / tan α) + ( p / tan β)


By replacing p = a tan α we get,


= a (1 + tan α cotβ) m

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