Let the radius of park including track (i.e. outside circle) be 'r 1 ' and radius of park without including (i.e. inner circle) track be 'r 2 '.
Given,
Circumference of Park = 314 m
we know that,
circumference of a circle = 2πr
where 'r' is the radius of the circle.
⇒ 2πr 1 = 314
⇒ 2 × 3.14 × r 1 = 314
⇒ 2r 1 = 100 m
⇒ r 1 = 50 m
Also, area of circle = πr 2 , where 'r' is the radius of circle.
⇒ area of outer circle = πr 1 2 = 3.14 × (50) 2 = 7850 m 2 [1]
Also,
Radius of park excluding the track, r 2 = r 1 - width of track = 50 - 20 = 30 m
⇒ area of inner circle = πr 2 2 = 3.14 × (30) 2 = 2826 m 2
Now,
Area of laying turf in the park = area of inner circle = 2826 m 2
Cost of laying 1 m 2 = 1.25 Rs
⇒ Cost of laying 2826 m 2 = 2826(1.25) = 3532.5 Rs
Also,
Area of track = Area of outer circle - Area of inner circle
⇒ Area of track = 7850 - 2826 = 5024 m 2
Cost of concrete 1 m 2 of track = 1.25 Rs
Cost of concrete 5024 m 2 of track = 5024(1.25) = 6280 Rs