Write structures of the products of the following reactions:
In this reaction, when 2-Methylbutanal reacts with the given reagent NaBH4, then the double bond between carbon and oxygen gets to break down in the above aldehyde compound, where carbon has positive charge and oxygen will have a negative charge on them. So, H+ gets placed on the carbon to complete its octet and H+ gets substituted on O- to form OH, i.e, an alcohol. Thus we get 2-Methylbutan-1-ol as a product.
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