Show that the area of the triangle contained between the vectors a and b is one half of the magnitude of a × b.
Consider two vectors
(OK) and
(OM) are making angle θ which each other as shown in following figure,

Now,
In ΔOMN we can write the equation,

⇒ ![]()
We know that magnitude of cross product of vectors a and b is,
![]()
=
(∵
)
=
×OK×MN (∵
= 1)
= 2×Area of ΔOMK
∴ Area of ΔOMK = 
Hence Proved.