In three moles of ethane (C₂H₆), calculate the following:

(i) Number of moles of carbon atoms.

(ii) Number of moles of hydrogen atoms.

(iii) Number of molecules of ethane.

In 1 mole of ethane (C₂H₆), it is seen that 2 moles of carbon and 6 moles of hydrogen is present.

(i) Since three moles of ethane is present,

So, Number of moles of carbon present = 3×2

= 6

Therefore 6 moles of carbon is present in 3 moles of ethane.

(ii) Since three moles of ethane is present,

So, Number of moles of hydrogen present = 3×6

= 18

Therefore 18 moles of hydrogen is present in 3 moles of ethane.

(iii) 1 mole of ethane contains 6.023×10²³ molecules of ethane [By Avogadro’s Law]

Therefore, Number of molecules if ethane in 3 moles of ethane

= 3×6.023×10²³

= 18.069×10²³

Therefore, Number of molecules of ethane present in 3 moles of ethane is 18.069×10²³