What is the concentration of sugar (C₁₂H₂₂O₁₁) in mol L^–1 if its 20 g are dissolved in enough water to make a final volume up to 2L?

Given:

Mass of sugar = 20g

Volume of solution = 2 L

Atomic Mass of Hydrogen = 1g

Atomic Mass of Oxygen = 16g

Atomic Mass of Carbon = 12g

So Molecular Mass of sugar = [12×12] + [22×1] + [16×11]

= 144 +22 + 176

= 342 g

Number of moles of sugar = [Mass of sugar]/ Molecular Mass of sugar

= 20/342

= 0.05848

Molarity, M_o

= 0.0292 mol/L

≈ 0.029 mol/L