An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.


Given:

Mass Number = 37


Percentage of neutron = 11.1% more as compared electrons


Let Number of electrons = number of protons = p


Let number of protons = p


Let number of neutrons= n


p + n = 81


p + {p + [11.1× p] / 100} = 37


p + 1.111p = 37


2.111p = 37


p = 37 / 2.111


p = 17.527


p = 17


Atomic Number = 17


The element is chlorine.


The atomic symbol is 3717Cl.


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