Indicate the number of unpaired electrons in:

(a) P - 1s² 2s² 2p⁶ 3s² 3p³

(b) Si - 1s² 2s² 2p⁶ 3s² 3p²

(c) Cr - 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵

(d) Fe - 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

(e) Kr - 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶

(a) Therefore, number of unpaired electron = 3

(b) Therefore, number of unpaired electron = 2 [as p orbital can have a maximum of 6 electrons]

(c) Therefore, number of unpaired electron = 6

(d)Therefore number of unpaired electron = 4

(e) Krypton has no unpaired electron as it is noble gas.