The size of isoelectronic species — F, Ne and Na+ is affected by

(a) nuclear charge (Z)


(b) valence principal quantum number (n)


(c) electron-electron interaction in the outer orbitals


(d) none of the factors because their size is the same.


The size of an isoelectronic species increases with a decrease in the nuclear charge (Z).

For example, the order of the increasing nuclear charge of F-, Ne, and Na+ is as follows:


F-(Z=9) < Ne(Z=10) < Na+(Z=11)


Therefore, the order of the increasing size of F-, Ne and Na+ is as follows:


Na+ < Ne < F-


Hence, the correct option is - (a) nuclear charge (Z).


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