A vessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35°C. What would be its pressure?


Given,

Initial pressure, P1 = 1.2 bar


Initial volume, V1 = 120 ml


Final volume, V2 = 180 ml


Since the temperature remains constant, the final pressure (P2) can be calculated using


Boyle's law.


According to Boyle's law,


P1V1 = P2V2


P1V1 = P2V2


⇒


⇒ P2 =


⇒ P2 = 2.5 bar


Therefore, the pressure would be 0.8 bar.


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