Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
(R = 0.083 bar dm3 K–1 mol–1).
Given:
Number of moles, n = 4
Volume, V = 5 dm3
Pressure, P = 3.32 bar
Universal gas constant, R = 0.083 bar dm3 K–1 mol–1
Let the temperature be T.
Then, from ideal gas equation we know that: -
PV = nRT
= 50K
Hence, the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar is 50K.