It has been found that the pH of a 0.01M solution of an organic acid is 4.15. Calculate the concentration of the anion, the ionization constant of the acid and its pKa.
Given:
pH of = 4.15
Concentration of HA = 0.01M
To calculate the concentration of the anion, we apply the formula:
pH = -log[H+]
To calculate the ionization constant of the acid, we apply the formula:
Ka =
To calculate the pKa of an organic acid, we apply the formula:
pKa = -log ka
where Ka is the ionization constant of the acid
Let the HA be the acid
The ionization of organic acid HA is HA ⇌ H+ + A-
pH = -log[H+]
We can also write,
log[H+] = -pH
As pH = 4.15 (given)
∴ log[H+] = -4.15
By taking antilog of both the sides, we get
[H+] = 7.08 × 10-5
[A-] = [H+] = 7.08 × 10-5 M
Thus, the concentration of anion is 7.08 × 10-5M
Ka =
Ka =
As [A-] = [H+] = 7.08 × 10-5 (calculated above)
[HA] = 10-2 (given)
∴ Ka =
⇒Ka = 5.0 × 10-7
Thus, the ionization constant of the acid is 5.0 × 10-7
pKa = -log ka
As Ka = 5.0 × 10-7
∴ pKa = -log (5.0 × 10-7)
⇒pKa = - log 5 – (-7) log 10
⇒pKa = 7 - log 5
⇒pKa = 7 – 0.699
⇒pKa = 6.301
Thus, pka is 6.301
Note: pKa is a measure of acid strength. It depends on the identity and chemical properties of the acid. pH is a measure of [H+] in a solution. For acids, the smaller the pKa, the more acidic the substance is (the more easily a proton is lost, thus the lower the pH).