Suggest a list of the substances where carbon can exhibit oxidation states from–4 to + 4 and nitrogen from –3 to + 5.


The substances where carbon can exhibit oxidation states from -4 to + 4 are following:-


Let the O.N. of C be ‘x’


Substances



O.N. of carbon



Calculation



CH4



-4



x + 4(+ 1) = 0


x = -4



H3C-CH3



-3



3(1) + x + x + 3(1) = 0


X = -3



CH3Cl



-2



x + 3(+ 1) + 1(-1) = 0


x = -2



HC = CH



-1



1 + x + x + 1 = 0


X = -1



CH2Cl2



0



x + 2(1) + 2(-1) = 0


x = 0



ClC = CCl



+ 1



1(-1) + x + x + 1(-1) = 0


X = + 1



CO



+ 2



x + 1(-2) = 0


x = + 2



Cl3C-CCl3



+ 3



3(-1) + x + x + 3(-1) = 0


X = + 3



CCl4



+ 4



x + 4(-1) = 0


x = + 4



The substances where Nitrogen can exhibit oxidation states from -3 to + 5 are following:-


Let the O.N. of N be ‘y’


Substances



O.N. of N



Calculations



NH3



-3



y + 3(1) = 0


y = -3



N2H4



-2



2y + 4(1) = 0


y = -2



N2H2



-1



2y + 2(1) = 0


y = -1



N2



0



2y = 0


y = 0



N2O



+ 1



2y + 1(-2) = 0


y = + 1



NO



+ 2



y + 1(-2) = 0


y = + 2



N2O3



+ 3



2y + 3(-2) = 0


y = + 3



NO2



+ 4



y + 2(-2) = 0


y = + 4



N2O5



+ 5



2y + 5(-2) = 0


y = + 5



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