Balance the following redox reactions by ion – electron method:
H2O2 (aq) + Fe2+ (aq) → Fe3+ (aq) + H2O (l) (in acidic solution)
Following the steps as in part (A), we have the oxidation half reaction equation as:-
Fe2+(aq)→ Fe3+(aq) + e-
And the reduction half reaction as:-
H2O2(aq) + 2H+(aq) + 2e-→ 2H2O
Multiplying the oxidation half reaction by 2 and then adding it to the reduction half reaction, we have the net balanced redox reaction as:-
H2O2(aq) + 2Fe2+(aq) + 2H+(aq)→ 2 Fe3+(aq) + 2H2O