Arrange the bonds in order of increasing ionic character in the molecules: LiF, K₂O, N₂, SO_2, and ClF₃.

N₂ < SO₂ <CIF₃ < K₂O < LiF

Explanation: First, we have to find out the ionic character in each molecule. As we know that ionic character in a molecule depends upon the electronegativity difference between the atoms. The higher the electronegativity difference, higher will be the ionic character.

LiF = The electronegativity of Li is 0.98 and electronegativity of F are 3.98. Hence the electronegativity difference between Li—F atoms is 3

K₂O = The electronegativity of K is 0.82 and the electronegativity of oxygen is 3.4. Hence the electronegativity difference between

K₂—O atoms is 2.58

N₂ = The electronegativity of N is 3.04. Hence the electronegativity difference between N—N atoms is 0

SO₂ = The electronegativity of S is 2.58 and the electronegativity of oxygen is 3.4. Hence the electronegativity difference between

S—O₂ atoms is 0.82

CIF₃ = The electronegativity of F, I and C is 3.9, 2.6 and 2.5 respectively. Hence the electronegativity difference between

C—I—F₃ atoms is 1.2

As 0 < 0.9 < 1.2 < 2.58 < 2.92

The ionic character increases with increase in the electronegativity difference.

∴ N₂ < SO₂ <CIF₃ < K₂O < LiF