For what values of x, the numbers
are in G.P.?
Given: ![]()
For the given Sequence to be in G.P. Common ratio between two adjacent numbers in the sequence should be equal.
That is: Common ratio between
= Common ratio between ![]()
![]()
![]()
⇒ (1)2 = x2
⇒ x = ![]()
⇒ x = ![]()
∴ For the given sequence to be in G.P. x should be
.