Solve each of the equation in Exercises 6 to 9:

27x2 – 10 x + 1 = 0


We have,


Now, in order to solve the equation we have to compare this with ax2 + bx + c = 0 where a = 27, b = - 10 and c = 1


Thus, the discriminant of the above given equation is:


D = b2 – 4ac


= (- 10)2 – 4 × 27 × 1


= 100 – 108


= - 8


Hence, the required solutions are:



=


=


=


8
1