In each of the following, find the equation of the circle with

Centre () and radius (1/12)

The equation of a circle with centre (h,k) and radius r is given as

(x-h)² + (y-k)²=r²

It is given that centre (h,k)= and radius(r) = .

Therefore, the equation of the circle is

⇒ x² – x + + y² -

⇒ x² – x + + y² -

⇒ x² – x + + y² -=0

⇒ 144x² -144x + 36 + 144y² -72y + 9- 1=0

⇒ 144x² -144x+ 144y² – 72y + 44 =0

⇒ 36x² +36x+ 36y² -18y+11 = 0

⇒ 36x² +36y² -36x – 18y+ 11= 0