A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine
(i) P(not A),
(ii) P(not B) and
(iii) P(A or B)
Given: P(A) = 0.42, P(B)= 0.48 and P(A and B) = 0.16
(i)
(ii)
= 0.42 + 0.48 – 0.16 = 0.74