A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine

(i) P(not A),


(ii) P(not B) and


(iii) P(A or B)


Given: P(A) = 0.42, P(B)= 0.48 and P(A and B) = 0.16


(i)


(ii)



= 0.42 + 0.48 – 0.16 = 0.74


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