A pole 6 m high casts a shadow 2 √3 m long on the ground, then find the angle of elevation of the sun.

Question

Philoid · Accepted Answer

Let AB be a pole such that AB = 6 m

And BC be its shadow such that BC = 2√3 m

Angle of elevation, θ = ∠ACB

In ΔABC

⇒ tan θ = √3

⇒ θ = 60°

i.e. Angle of elevation is 60°.

A pole 6 m high casts a shadow 2√3 m long on the ground, then find the angle of elevation of the sun.