The relation f is defined by
Show that f is a function and g is not a function.
Given:
As
⇒ f(x) = x2 for 0≤x<3
And f(x) = 3xfor 3≤x<10
At x = 3, f(x) = x2 = 32 = 9
Also, at x = 3, f(x) = 3x = 3×3 = 9
Hence, we see for 0≤x≤10, f(x) has unique images. Thus, by definition of a function the given relation is function.
Now,
As
⇒ g(x) = x2 for 0≤x<2
And g(x) = 3xfor 2≤x<10
At x = 2, g(x) = x2 = 22 = 4
Also, at x = 2, g(x) = 3x = 3×2 = 6
Hence, element 2 of the domain of relation g(x) corresponds to two different images i.e. 4 and 6.
because for 0≤x≤10, f(x) does not have unique images. Thus, by definition of a function the given relation is not a function.