Let f = {(1, 1), (2, 3), (0, –1), (–1, –3)} be a function from Z to Z defined by f(x) = ax + b, for some integers a, b. Determine a, b.


Given: f = {(1, 1), (2, 3), (0, –1), (–1, –3)}

f(x) = ax + b


(1,1) Є f for x = 1, f(x) = 1


1 = a(1) + b


a+b = 1 …. (1)


Similarly, (0, -1) Є f for x = 0, f(x) = -1


-1 = a(0) + b


b = -1


a-1 = 1 (from 1)


a = 2.


Hence a = 2 and b = -1.


8
1